C program for simple Calculator

The below code will create a simple calculator with the use of if-else-if control structure. 

Code:
#include<stdio.h>
#include<conio.h>

void main()
{
    int a,b,mod;
    float x,y,sum,sub,mul,div;
    char ch,op;

        printf("This is a calculator\nThe following operations can be perfoemed by it\n\naddition +\nsubtraction -\nmultiplication *\ndivision /\nremainder %%\n\nEnter your equation e.g \"3+4\" :");
        scanf("%f %c %f",&x, &op,&y);
        if(op=='+')
        {
            sum=x+y;
            printf("anwser is %.2f",sum);
        }
        else if(op=='-')
        {
            sub=x-y;
            printf("answer is %.2f",sub);
        }
        else if(op=='*')
        {
            mul=x*y;
            printf("answer is %.2f",mul);
        }
        else if(op=='/')
        {
            if(x==0||y==0)
            {
                printf("The entered number should not be zero");
            }
            else
            {
                div=x/y;
                printf("answer is %.2f",div);
            }
        }
        else if(op=='%')
        {
            a=x;
            b=y;
            mod=a%b;
            printf("mod is %d",mod);
        }
        else
            printf("invalid input");
        printf("\n\n\n(*_*) Would you like to run again...(Y/N)");
        scanf(" %c",&ch);
        if(ch=='Y'||ch=='y')
            {
                system("cls");
                main();
            }
        printf("\npress any key to continue");
        getch();


}

Filed Under: Simple C Programs Monday, 21 April 2014